From: Tom Fitzpatrick (tfitz@cadence.com)
Date: Mon Jan 11 1999 - 12:57:25 PST
BAD MSG:
Hi Stephen,
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>Example 4:
>always @* begin // equivalent to @(a or b or c or d)
> x = a ^ b;
> always @* // equivalent to @(c or d)
> x = c ^ d;
>end
Can't have a nested always. This would have to be:
always @* begin
x = a ^ b;
@*
x = c ^ d;
end
Equivalent to:
always @(a or b or c or d)
x = a ^ b;
@(c or d)
x = c ^ d;
end
Is that the correct intent?
Thanks,
-Tom
---------------
Tom Fitzpatrick
Senior Technical Marketing Manager Cadence Design Systems, Inc.
Cycle Simulation Products 270 Billerica Rd.
Logic Design and Verification Business Unit Chelmsford, MA 01824
x6438 (978)446-6438
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